ClF3 
n=2( No of lone pair present in equitorial plane ) (Unpaired e−) (A) V+3:[Ar]3 d22 (B) Ti3+:[Ar]3 d11 (C) Cu+2:[Ar]3 d91 (D) Ni+2:[Ar]3 d82 (E) Ti+2:[Ar]3 d22
Consider ' n ' is the number of lone pair of electrons present in the equatorial position of the most stable structure of ClF3. The ions from the following with ' n ' number of unpaired electrons are A. V3+ B. Ti3+ C. Cu2+ D. Ni2+ E. Ti2+ Choose the correct answer from the options given below:
Held on 28 Jan 2025 · Verified 6 Jul 2026.
A and C Only
A, D and E Only
B and D Only
B and C Only
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