More abundant isotope =B11 [Number of neutrons =6 ] $\begin{aligned}
& \mathrm{x}=6 \
& \mathrm{~B}+\mathrm{O}_2 \rightarrow \mathrm{B}_2 \mathrm{O}_3
\end{aligned}Oxidationstateof\mathrm{B}in\mathrm{B}_2 \mathrm{O}_3=+3So,y=3Hencex+y=9$
The number of neutrons present in the more abundant isotope of boron is ' x '. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is ' y '. The value of x+y is _______
Held on 5 Apr 2024 · Verified 6 Jul 2026.
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