Match List I with List II … Choose the correct answer from the options given below: - JEE Main 2024 Chemistry · Inorganic Chemistry PYQ

JEE Main 2024 — Chemistry Inorganic Chemistry

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Match List I with List II $\begin{array}{|l|l|l|l|} \hline & \text{List-I} & & \text{List-II} \\ \hline & \text{(Molecule)} & & \text{(Shape)} \\ \hline \text { A. } & \mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH}_2 \mathrm{O} & \text { I. } & \text { Violet } \\ \hline \text { B. } & {\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}^{4-}\right.} & \text { II. } & \text { Blood Red } A \\ \hline \text { C. } & {[\mathrm{Fe}(\mathrm{SCN})]^{2+}} & \text { III. } & \text { Prussian Blue } \\ \hline \text { D. } & \left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \cdot 12 \mathrm{MoO}_3 & \text { IV. } & \text { Yellow } \\ \hline \end{array}$ Choose the correct answer from the options given below:

Official previous-year question

Held on 8 Apr 2024 · Verified 6 Jul 2026.

Options

A
A-III, B-I, C-II, D-IV
B
A-I, B-II, C-III, D-IV
C
A-IV, B-I, C-II, D-III
D
A-II, B-III, C-IV, D-I

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Solution

$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3 \cdot \mathrm{xH}_2 \mathrm{O} \rightarrow$ Prussian Blue $\left[\mathrm{Fe}(\mathrm{CN})_5 \mathrm{NOS}\right]^{4-} \rightarrow$ Violet $[\mathrm{Fe}(\mathrm{SCN})]^{2+} \rightarrow$ Blood Red $\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \cdot 12 \mathrm{MoO}_3 \rightarrow$ Yellow

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JEE Main Inorganic Chemistry in other years

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