Oxygen can form 2pπ−2pπ multiple bond with itself due to its small size while sulphur cannot form multiple bond with itself as 3pπ−3pπ bond will be unstable due to large size of sulphur, but sulphur can form multiple bond with small size atom like C and N. $\begin{aligned}
& \text { eg. } \mathrm{S}=\mathrm{C}=\mathrm{S} \
& \mathrm{S}=\mathrm{C}=\mathrm{N}^{-} \leftrightarrow \mathrm{S}^{\ominus}-\mathrm{C} \equiv \mathrm{N}
\end{aligned}$
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Both rhombic and…
JEE Main 2024 — Chemistry Inorganic Chemistry
2024mcqmedium
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Both rhombic and monoclinic sulphur exist as S8 while oxygen exists as O2. Reason (R) : Oxygen forms pπ−pπ multiple bonds with itself and other elements having small size and high electronegativity like C,N, which is not possible for sulphur. In the light of the above statements, choose the most appropriate answer from the options given below :
Official previous-year question
Held on 9 Apr 2024 · Verified 6 Jul 2026.
Options
- A
(A) is correct but (R) is not correct
- B
(A) is not correct but (R) is correct
- C
Both (A) and (R) are correct and (R) is the correct explanation of (A)
- D
Both (A) and (R) are correct but (R) is not the correct explanation of (A)
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