Which of the following statements are correct? (A) The ${M}^{3+}/{M}^{2+}$ reduction potential for iron is greater than manganese. (B) The higher oxidation states of first row d-block elements get stabilized by oxide ion (C) Aqueous solution of ${\mathrm{Cr}}^{2+}$ can liberate hydrogen from dilute acid (D) Magnetic moment of ${V}^{2+}$ is observed between $4.4-5.2\mathrm{BM}$ Choose the correct answer from the options given below:

JEE Main 2023 — Chemistry Inorganic Chemistry

2023mcqmedium

Which of the following statements are correct?

(A) The ${M}^{3+}/{M}^{2+}$ reduction potential for iron is greater than manganese.

(B) The higher oxidation states of first row d-block elements get stabilized by oxide ion

(D) Magnetic moment of ${V}^{2+}$ is observed between $4.4-5.2\mathrm{BM}$

Choose the correct answer from the options given below:

Official previous-year question

Held on 10 Apr 2023 · Verified 6 Jul 2026.

Options

A
$(B),(C)$ only
B
$(A),(B),(D)$ only
C
$(C),(D)$ only
D
$(A),(B)$ only

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Solution

The valence electronic configuration of ${\mathrm{Mn}}^{3+}$ is $3{d}^{4}$ and that of ${\mathrm{Mn}}^{2+}$ is stable $3{d}^{5}$ .The valence electronic configuration of ${\mathrm{Fe}}^{3+}$ is $3{d}^{5}$ and that of ${\mathrm{Fe}}^{2+}$ is $3{d}^{6}$ .

The reduction electrode potential of ${\mathrm{Mn}}^{3+}/{\mathrm{Mn}}^{2+}$ is $+1.57V$ while that of ${\mathrm{Fe}}^{3+}/{\mathrm{Fe}}^{2+}$ is $+0.77V$ , hence A is wrong. Higher oxidation state of smaller $d$ -block elements is stabilised (or say form compounds) with smaller anion oxide that can be explained by stearic reason hence $B$ is correct.

The oxidation electrode potential of ${\mathrm{Cr}}^{2+}/{\mathrm{Cr}}^{3+}$ is $+0.41V$ hence, it can reduce ${H}^{+}$ and so liberate ${H}_{2}$ .

The unpaired electrons in ${V}^{2+}$ are $3$ hence, the magnetic moment of ${V}^{2+}$ will be lesser than $4.4\mathrm{BM}$ .

Hence, only $B$ and $C$ are correct.

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Solution

The oxidation electrode potential of ${\mathrm{Cr}}^{2+}/{\mathrm{Cr}}^{3+}$ is $+0.41V$ hence, it can reduce ${H}^{+}$ and so liberate ${H}_{2}$ .

The unpaired electrons in ${V}^{2+}$ are $3$ hence, the magnetic moment of ${V}^{2+}$ will be lesser than $4.4\mathrm{BM}$ .

Hence, only $B$ and $C$ are correct.

JEE Main 2023 — Chemistry Inorganic Chemistry

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JEE Main 2023 — Chemistry Inorganic Chemistry

Options

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Solution

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JEE Main Inorganic Chemistry in other years

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Physical Chemistry

Organic Chemistry

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