JEE Main 2023 — Chemistry Inorganic Chemistry

2023integereasy

The observed magnetic moment of the complex $[\mathrm{Mn}(\mathrm{NCS}{)}_{6}){]}^{x-}$ is $6.06\mathrm{BM}$ . The numerical value of $x$ is

Official previous-year question

Held on 8 Apr 2023 · Verified 6 Jul 2026.

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Solution

The complex $[\mathrm{Mn}(\mathrm{NCS}{)}_{6}){]}^{x-}$ has a magnetic moment of $6.06\mathrm{BM}$ . This indicates that the complex has unpaired electrons, which contribute to its magnetic moment.

Number of unpaired electrons $=5$ $({\mathrm{Mn}}^{2+}:3{d}^{5})$ .

So $\mathrm{Mn}$ must be in $+2$ oxidation state ${\mathrm{Mn}}^{2+}$ .

$\Rightarrow 2+(–6)=–x \Rightarrow –4=–x \Rightarrow x=4$

The numerical value of $x$ is $4$ , so the complex is $[\mathrm{Mn}(\mathrm{NCS}{)}_{6}){]}^{4-}$ .

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JEE Main 2023 — Chemistry Inorganic Chemistry

2023integereasy

The observed magnetic moment of the complex $[\mathrm{Mn}(\mathrm{NCS}{)}_{6}){]}^{x-}$ is $6.06\mathrm{BM}$ . The numerical value of $x$ is

Official previous-year question

Held on 8 Apr 2023 · Verified 6 Jul 2026.

Did you get this right?

Solution

The complex $[\mathrm{Mn}(\mathrm{NCS}{)}_{6}){]}^{x-}$ has a magnetic moment of $6.06\mathrm{BM}$ . This indicates that the complex has unpaired electrons, which contribute to its magnetic moment.

Number of unpaired electrons $=5$ $({\mathrm{Mn}}^{2+}:3{d}^{5})$ .

So $\mathrm{Mn}$ must be in $+2$ oxidation state ${\mathrm{Mn}}^{2+}$ .

$\Rightarrow 2+(–6)=–x \Rightarrow –4=–x \Rightarrow x=4$

The numerical value of $x$ is $4$ , so the complex is $[\mathrm{Mn}(\mathrm{NCS}{)}_{6}){]}^{4-}$ .

JEE Main 2023 — Chemistry Inorganic Chemistry

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JEE Main 2023 — Chemistry Inorganic Chemistry

Did you get this right?

Solution

Your note

JEE Main Inorganic Chemistry in other years

More JEE Main Inorganic Chemistry questions

Other Chemistry topics for JEE Main

Physical Chemistry

Organic Chemistry

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