The atomic number of Neodymium (Nd) is 60. Its electronic configuration is [Xe]4f46s2.
Now, by removing two electrons from the outermost shell 6s, Nd2+ ion is formed. Hence, electronic configuration of Nd2+ is [Xe]4f4.
{\mathrm{Nd}}^{2+}=______
Held on 31 Jan 2023 · Verified 6 Jul 2026.
4f26s2
4f4
4f3
4f46s2
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