In chromyl chloride (CrO2Cl2), the oxidation state of chromium (Cr) is +6.
So, Cr(VI)=[Ar]183d0
For the given elements the configuration is,Mn(VII)=[Ar]183d0
Fe(III)=[Ar]183d5
Ti(III)=[Ar]183d1
V(IV)=[Ar]183d1
So among the given options Mn(VII) and Cr(VI) will have same number of d-electrons.