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Compound A reacts with NH_4 Cl and forms a compound B. Compound B reacts with H_2O and excess of CO_2 to form compound C which on passing through or…

JEE Main 2023 — Chemistry Inorganic Chemistry

2023mcqhard

Compound A reacts with NH4Cl{\mathrm{NH}}_{4}\mathrm{Cl}NH4​Cl and forms a compound B. Compound B reacts with H2O{H}_{2}OH2​O and excess of CO2{\mathrm{CO}}_{2}CO2​ to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A. B and C, are respectively.

Official previous-year question

Held on 25 Jan 2023 · Verified 6 Jul 2026.

Options

  1. A

    CaCl2,NH3,NH4HCO3{\mathrm{CaCl}}_{2},{\mathrm{NH}}_{3},{\mathrm{NH}}_{4}{\mathrm{HCO}}_{3}CaCl2​,NH3​,NH4​HCO3​

  2. B

    CaCl2,NH4+,(NH4)2CO3{\mathrm{CaCl}}_{2},{\mathrm{NH}}_{4}^{+},{({\mathrm{NH}}_{4})}_{2}{\mathrm{CO}}_{3}CaCl2​,NH4+​,(NH4​)2​CO3​

  3. C

    Ca(OH)2,NH3,NH4HCO3\mathrm{Ca}(\mathrm{OH}{)}_{2},{\mathrm{NH}}_{3},{\mathrm{NH}}_{4}{\mathrm{HCO}}_{3}Ca(OH)2​,NH3​,NH4​HCO3​

  4. D

    Ca(OH)2,NH4+,(NH4)2CO3\mathrm{Ca}(\mathrm{OH}{)}_{2},{\mathrm{NH}}_{4}^{+},{({\mathrm{NH}}_{4})}_{2}{\mathrm{CO}}_{3}Ca(OH)2​,NH4+​,(NH4​)2​CO3​

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