The compound which possess aromatic character will show highest dipole moment. From the given compounds the following compound will have the highest dipole moment. Because the Positive and negative ends acquire aromaticity.

JEE Main 2023 — Chemistry Inorganic Chemistry
Among the following compounds, the one which shows highest dipole moment is
Held on 13 Apr 2023 · Verified 6 Jul 2026.




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Two p-block elements X and Y form fluorides of the type $\mathrm{EF}_{3}$. The fluoride compound $\mathrm{XF}_{3}$ is a Lewis acid and $\mathrm{YF}_{3}$ is a Lewis base. The hybridizations of the central atoms of $\mathrm{XF}_{3}$ and $\mathrm{YF}_{3}$ respectively are
Elements X and Y belong to Group 15. The difference between the electronegativity values of ' X ' and phosphorus is higher than that of the difference between phosphorus and ' Y '. ' X ' \& ' Y ' are respectively
Identify the correct statements from the following A. $[Fe(C_2O_4)_3]^{3-}$ is the most stable complex among $[Fe(OH)_6]^{3-}$, $[Fe(C_2O_4)_3]^{3-}$ and $[Fe(SCN)_6]^{3-}$ B. The stability of $[Cu(NH_3)_4]^{2+}$ is greater than that of $[Cu(en)_2]^{2+}$ C. The hybridization of Fe in $K_4[Fe(CN)_6]$ is $d^2sp^3$ D. $[Fe(NO_2)_3Cl_3]^{3-}$ exhibits linkage isomerism E. $NO_2^-$ and $SCN^-$ ligands are NOT ambidentate ligands Choose the correct answer from the options given below :
Given below are two statements : Statement I : The number of species among $\mathrm{SF}_{4}, \mathrm{NH}_{4}^{+},\left[\mathrm{NiCl}_{4}\right]^{2-}, \mathrm{XeF}_{4},\left[\mathrm{PtCl}_{4}\right]^{2-}, \mathrm{SeF}_{4}$ and $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}$, that have tetrahedral geometry is 3. Statement II : In the set [$\mathrm{NO}_{2}, \mathrm{BeH}_{2}, \mathrm{BF}_{3}, \mathrm{AlCl}_{3}$], all the molecules have incomplete octet around central atom. In the light of the above statements, choose the correct answer from the options given below :
The correct set that contains all kinds (basic, acidic, amphoteric and neutral) of oxides is:
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