(i) Molecular orbital configuration of O22− is KK(σ2s)2(σ∗2s)2𝜋(2px)2𝜋(2py)2(σ2pz)2𝜋∗(2px)2𝜋∗(2py)2
Bond order = 21(Nb−Na) = 21(8−6)=1
(ii) Molecular orbital configuration of CO is KK(σ2s)2(σ∗2s)2𝜋(2px)2𝜋(2py)2(σ2pz)2
Bond order = 21(Nb−Na) = 21(8−2)=3
(iii) Molecular orbital configuration of NO+ is KK(σ2s)2(σ∗2s)2𝜋(2px)2𝜋(2py)2(σ2pz)2
Bond order = 21(Nb−Na) = 21(8−2)=3
So, according to molecular orbital theory, the bond orders respectively are 1, 3 and 3.