Ce+2:(xe)4f2
Eu+2:(xe)4f7
Sm+2:(xe)4f6
Yb+2:(xe)4f14
As Yb+2andEu+2 has completely filled and half filled 4f orbital, so they would be the most stable. But among the these two Eu+2 is more stable based on reduction potential value.
EM3+/M2+∘⇒Eu−0.35Yb−1.05
Hence, due to more reduction potential in Eu as compared to Yb, it can concluded that Eu2+ is more stable than Yb2+.