Skip to main content

The geometry around boron in the product 'B' formed from the following reaction is BF_3+ NaHoverset450K longrightarrow A+ NaF A+ NMe_3→ B

JEE Main 2022 — Chemistry Inorganic Chemistry

2022mcqmedium

The geometry around boron in the product 'BBB' formed from the following reaction is

BF3+NaH⟶450KA+NaF{\mathrm{BF}}_{3}+\mathrm{NaH}\overset{450K}{\longrightarrow }A+\mathrm{NaF}BF3​+NaH⟶450K​A+NaF

A+NMe3→BA+{\mathrm{NMe}}_{3}\rightarrow BA+NMe3​→B

Official previous-year question

Held on 25 Jul 2022 · Verified 6 Jul 2026.

Options

  1. A

    trigonal planar

  2. B

    tetrahedral

  3. C

    pyramidal

  4. D

    square planar

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

JEE Main Inorganic Chemistry in other years

More JEE Main Inorganic Chemistry questions

Other Chemistry topics for JEE Main

Keep practicing Inorganic Chemistry

Work through every JEE Main Inorganic Chemistry PYQ, year by year.

Browse all Chemistry topics