Bond order =2Nb−Na
NB= Number of electrons in bonding molecular orbitals.
NA⋅B= Number of electrons in anti bonding molecular orbitals.
C22− has 14 electrons, it is isoelectronic with N2 where Bond order =3,
N22− has 16 electrons is isoelectronic with O2 whose bond order =2
O22− has 18 electrons and is isoelectronic with F2 whose bond order =1
So, the correct order of Bond order is
C22−>N22−>O22−.