Match List-I with List-II, match the gas evolved during each reaction. List-I List-II A ${({\mathrm{NH}}_{4})}_{2}{\mathrm{Cr}}_{2}{O}_{7}\overset{\Delta }{\longrightarrow }$ I ${H}_{2}$ B ${\mathrm{KMnO}}_{4}+\mathrm{HCl}\rightarrow$ II ${N}_{2}$ C $\mathrm{Al}+\mathrm{NaOH}+{H}_{2}O\rightarrow$ III ${O}_{2}$ D ${\mathrm{NaNO}}_{3}\overset{\Delta }{\longrightarrow }$ IV ${\mathrm{Cl}}_{2}$ Choose the correct answer from the options given below

JEE Main 2022 — Chemistry Inorganic Chemistry

2022mcqhard

Match List-I with List-II, match the gas evolved during each reaction.

	List-I		List-II
A	${({\mathrm{NH}}_{4})}_{2}{\mathrm{Cr}}_{2}{O}_{7}\overset{\Delta }{\longrightarrow }$	I	${H}_{2}$
B	${\mathrm{KMnO}}_{4}+\mathrm{HCl}\rightarrow$	II	${N}_{2}$
C	$\mathrm{Al}+\mathrm{NaOH}+{H}_{2}O\rightarrow$	III	${O}_{2}$
D	${\mathrm{NaNO}}_{3}\overset{\Delta }{\longrightarrow }$	IV	${\mathrm{Cl}}_{2}$

Choose the correct answer from the options given below

Official previous-year question

Held on 28 Jul 2022 · Verified 6 Jul 2026.

Options

A
$A-\mathrm{II},B-\mathrm{III},C-I,D-\mathrm{IV}$
B
$A-\mathrm{III},B-I,C-\mathrm{IV},D-\mathrm{II}$
C
$A-\mathrm{II},B-\mathrm{IV},C-I,D-\mathrm{III}$
D
$A-\mathrm{III},B-\mathrm{IV},C-I,D-\mathrm{II}$

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Solution

Thermal decomposition of ammonium dichromate ${({\mathrm{NH}}_{4})}_{2}{\mathrm{Cr}}_{2}{O}_{7}$ on heating gives ${N}_{2},{\mathrm{Cr}}_{2}{O}_{3}$ and ${H}_{2}O$ as follows:

${({\mathrm{NH}}_{4})}_{2}{\mathrm{Cr}}_{2}{O}_{7}\overset{\Delta }{\rightarrow }{N}_{2}+{\mathrm{Cr}}_{2}{O}_{3}+4{H}_{2}O$

$2{\mathrm{KMnO}}_{4(s)}+16\mathrm{HCl}(\mathrm{aq})\rightarrow 2\mathrm{KCl}(\mathrm{aq})+2{\mathrm{MnCl}}_{2(\mathrm{aq})}+8{H}_{2}O(l)+5{\mathrm{Cl}}_{2(g)}$

The reaction of Aluminium with Sodium hydroxide $(\mathrm{Al}+\mathrm{NaOH})$ gives a salt and Hydrogen gas.

$2\mathrm{Al}(s)+2\mathrm{NaOH}(l)+6{H}_{2}O(l)\rightarrow 2\mathrm{Na}[\mathrm{Al}{(\mathrm{OH})}_{4}](s)+3{H}_{2}(l)$

On heating sodium nitrate it undergoes decomposition reaction and liberates oxygen and convert into sodium nitrite.

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Options

$A-\mathrm{II},B-\mathrm{III},C-I,D-\mathrm{IV}$

$A-\mathrm{III},B-I,C-\mathrm{IV},D-\mathrm{II}$

$A-\mathrm{II},B-\mathrm{IV},C-I,D-\mathrm{III}$

$A-\mathrm{III},B-\mathrm{IV},C-I,D-\mathrm{II}$

Solution

Thermal decomposition of ammonium dichromate ${({\mathrm{NH}}_{4})}_{2}{\mathrm{Cr}}_{2}{O}_{7}$ on heating gives ${N}_{2},{\mathrm{Cr}}_{2}{O}_{3}$ and ${H}_{2}O$ as follows:

${({\mathrm{NH}}_{4})}_{2}{\mathrm{Cr}}_{2}{O}_{7}\overset{\Delta }{\rightarrow }{N}_{2}+{\mathrm{Cr}}_{2}{O}_{3}+4{H}_{2}O$

$2{\mathrm{KMnO}}_{4(s)}+16\mathrm{HCl}(\mathrm{aq})\rightarrow 2\mathrm{KCl}(\mathrm{aq})+2{\mathrm{MnCl}}_{2(\mathrm{aq})}+8{H}_{2}O(l)+5{\mathrm{Cl}}_{2(g)}$

The reaction of Aluminium with Sodium hydroxide $(\mathrm{Al}+\mathrm{NaOH})$ gives a salt and Hydrogen gas.

$2\mathrm{Al}(s)+2\mathrm{NaOH}(l)+6{H}_{2}O(l)\rightarrow 2\mathrm{Na}[\mathrm{Al}{(\mathrm{OH})}_{4}](s)+3{H}_{2}(l)$

On heating sodium nitrate it undergoes decomposition reaction and liberates oxygen and convert into sodium nitrite.

JEE Main 2022 — Chemistry Inorganic Chemistry

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JEE Main 2022 — Chemistry Inorganic Chemistry

Options

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Solution

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JEE Main Inorganic Chemistry in other years

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