
B2H6 have four2c−2e bonds and two3c−2e bonds. Bridging bonds have larger bond length than terminal bonds. Angle between terminal bonds is more than angle between bridging bonds if all 4 terminal bonds are in one plane then bridging bonds are in perpendicular plane.
3NaBH4+4BF3450K⟶ether3NaBF4+2B2H6
Therefore we can say that only statement (C) and (D) are correct.