Number of hybrid orbitals = Number of bond pair + number of lone pair on central atom.
To have sp3d2 hybridisation there should be total of 6 (bond pairs + lone pairs). The structure in such case will be octahedral or its derivative structures.
Consider, PF5,BrF5,PCl3,SF6,[ICl4]−,ClF3 and IF5
Amongst the above molecule(s) ion(s), the number of molecule(s)/ion(s) having sp3d2 hybridisation is
Held on 29 Jul 2022 · Verified 6 Jul 2026.
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