JEE Main 2022 — Chemistry Inorganic Chemistry

2022mcqmedium

Borazine, also known as inorganic benzene, can be prepared by the reaction of $3$ -equivalents of " $X$ " with $6$ -equivalents of " $Y$ ". " $X$ " and " $Y$ ", respectively are

Official previous-year question

Held on 26 Jul 2022 · Verified 6 Jul 2026.

Options

A
$B{(\mathrm{OH})}_{3}$ and ${\mathrm{NH}}_{3}$
B
${B}_{2}{H}_{6}$ and ${\mathrm{NH}}_{3}$
C
${B}_{2}{H}_{6}$ and ${\mathrm{HN}}_{3}$
D
${\mathrm{NH}}_{3}$ and ${B}_{2}{O}_{3}$

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Solution

Reaction of ammonia with diborane gives initially ${B}_{2}{H}_{6}.2{\mathrm{NH}}_{3}$ which is formulated as ${[{\mathrm{BH}}_{2}{({\mathrm{NH}}_{3})}_{2}]}^{+}{[{\mathrm{BH}}_{4}]}^{-};$ further heating gives borazine, ${B}_{3}{N}_{3}{H}_{6}$ known as ''inorganic benzene'' in view of its ring structure with alternate $\mathrm{BH}$ and $\mathrm{NH}$ groups.

$3{B}_{2}{H}_{6}+6{\mathrm{NH}}_{3}\rightarrow 3{[{\mathrm{BH}}_{2}{({\mathrm{NH}}_{3})}_{2}]}^{+}{[{\mathrm{BH}}_{4}]}^{-}\overset{\mathrm{Heat}}{\rightarrow }2{B}_{3}{N}_{3}{H}_{6}+12{H}_{2}$

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JEE Main 2022 — Chemistry Inorganic Chemistry

2022mcqmedium

Borazine, also known as inorganic benzene, can be prepared by the reaction of $3$ -equivalents of " $X$ " with $6$ -equivalents of " $Y$ ". " $X$ " and " $Y$ ", respectively are

Official previous-year question

Held on 26 Jul 2022 · Verified 6 Jul 2026.

Options

A
$B{(\mathrm{OH})}_{3}$ and ${\mathrm{NH}}_{3}$
B
${B}_{2}{H}_{6}$ and ${\mathrm{NH}}_{3}$
C
${B}_{2}{H}_{6}$ and ${\mathrm{HN}}_{3}$
D
${\mathrm{NH}}_{3}$ and ${B}_{2}{O}_{3}$

Did you get this right?

Solution

$3{B}_{2}{H}_{6}+6{\mathrm{NH}}_{3}\rightarrow 3{[{\mathrm{BH}}_{2}{({\mathrm{NH}}_{3})}_{2}]}^{+}{[{\mathrm{BH}}_{4}]}^{-}\overset{\mathrm{Heat}}{\rightarrow }2{B}_{3}{N}_{3}{H}_{6}+12{H}_{2}$

JEE Main 2022 — Chemistry Inorganic Chemistry

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JEE Main 2022 — Chemistry Inorganic Chemistry

Options

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Solution

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JEE Main Inorganic Chemistry in other years

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Other Chemistry topics for JEE Main

Physical Chemistry

Organic Chemistry

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