Electronic configuration of divalent metal ion having atomic number 25 is

Total number of unpaired electrons=5
μ (Magnetic moment) =n(n+2)BM
where n= number of unpaired e
∴μ=5(5+2)=35B.M.=5.92B.M.
What is the spin-only magnetic moment value (B.M.) of a divalent metal ion with atomic number 25, in its aqueous solution?
Held on 17 Mar 2021 · Verified 6 Jul 2026.
5.92
5.0
zero
5.26
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