Complex
(i) [FeF6]3−Fe3+⇒[Ar]3d5,F− is WFL

n=5,μ=35B.M
(ii)[Co(NH3)6]3+⇒Co3+[Ar]3d6,NH3 is SFL

n=0,μ=0B.M
(iii) [NiCl4]2−Ni2+⇒[Ar]3d8,Cl−→WFL

n=2,μ=8B.M
(iv) [Cu(NH3)4]2+Cu2+⇒[Ar]3d9,NH3→SFL

n=1,μ=3B.M
Thus correct order of spin only magnetic moment is
(i)>(iii)>(iv)>(ii)