Diborane is prepared by the reaction of NaBH4 with I2. 2NaBH4+I2→B2H6+2NaI+H2
In diborane, B is sp3 hybridized. It is non-planar molecule and it has two 3c−2e− bonds.
Given below are the statements about diborane
(a) Diborane is prepared by the oxidation of NaBH4 with I2
(b) Each boron atom is in sp2 hybridized state
(c) Diborane has one bridged 3 centre-2-electron bond
(d) Diborane is a planar molecule
The option with correct statement(s) is
Held on 22 Jul 2021 · Verified 6 Jul 2026.
(c) and (d) only
(a) only
(c) only
(a) and (b) only
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