(i) [XeF5]−
St. No. =(5+2)=7 so hybridisation is=sp3d3 and structure is pentagonal planar.

(ii) XeO3F2 St. No. =5
so hybridisation is =sp3d and structure is trigonal bipyramidal.

JEE Main 2020 — Chemistry Inorganic Chemistry
The shape/structure of[XeF5]− and XeO3F2, respectively are :
Held on 2 Sept 2020 · Verified 6 Jul 2026.
pentagonal planar and trigonal bipyramidal
octahedral and square pyramidal
trigonal bipyramidal and pentagonal planar
trigonal bipyramidal and trigonal bipyramidal
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