The reaction of H3N3B3Cl3(A) with LiBH4 in tetrahydrofuran gives inorganic benzene (B) . Further, the reaction of (A) with (C) leads to H3N3B3(Me)3 . Compounds (B) and (C) respectively, are:
Held on 9 Jan 2020 · Verified 6 Jul 2026.
Bogging god MeBr
Diborane and MeMgBr
Boron nitride and MeBr
Borazine and MeMgBr
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First and second ionization enthalpies of lithium are $520$ kJ mol$^{-1}$ and $7297$ kJ mol$^{-1}$ respectively. Energy required to convert $3.5$ mg lithium (g) into $\text{Li}^{2+}$(g) $[\text{Li(g)} \rightarrow \text{Li}^{2+}\text{(g)}]$ is _______ kJ mol$^{-1}$. (nearest integer) [Molar mass of Li $= 7$ g mol$^{-1}$]
Regarding the hydrides of group 15 elements $\mathrm{EH}_{3}(\mathrm{E}=\mathrm{N}, \mathrm{P}, \mathrm{As}, \mathrm{Sb})$, select the correct statement from the following: A. The stability of hydrides decreases down the group. B. The basicity of hydrides decreases down the group. C. The reducing character increases down the group. D. The boiling point increases down the group. Choose the correct answer from the options given below:
Which of the following elements has the highest electronegativity?
Which of the following elements has the highest electronegativity?
In a period, the first ionisation enthalpy of the element at extreme left and the negative electron gain enthalpy of the extreme right element, except noble gases, are respectively.
Work through every JEE Main Inorganic Chemistry PYQ, year by year.