Ionization Enthalpy values indicate that the metal belongs to Ist group, since the second ionization enthalpy is very high.
(Q - only one valence electron)
Metal hydroxide will be of the type, MOH.
(1mol)MOH+(1mol)HCl→MCl+H2O
MOH+21H2SO4→21M2SO4+H2O
(1mol)(21mol) So, one mole of HCl is required to react with one mole of MOH.
So, 21 mole of H2SO4 is required to react with one mole of MOH.