Number of Geometrical Isomers in square planar [PdFClBr]2− are =3
Hence, n=3
[Fe(CN)6]3−
Fe3+=3d5, According to CFT, configuration is t2g221eg00; it means number of unpaired electron (n)=1
So spin-only magnetic moment
μ=n(n+2)=1.73BM
CFSE=(−0.4Δ0×nt2g)+(0.6Δ0×neg) =−0.4Δ0×5=−2.0Δ0