lp of N in N(CH3)3 is free to donate while in N(SiH3)3 lp is involved in back bonding so it is not easy to donate hence it is less basic.
Due to back bonding it is planar and sp2 hybridised.
The correct statement among the following is:
Held on 12 Apr 2019 · Verified 6 Jul 2026.
(SiH3)3N is planar and less basic than (CH3)3N
(SiH3)3N is pyramidal and more basic than (CH3)3N
(SiH3)3N is pyramidal and less basic than (CH3)3N
(SiH3)3N is planar and more basic than (CH3)3N
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