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The coordination number of Th in K_4 [ Th ( C_2 O_4 )_4 ( H_2 O )_2 ] is: ( C_2 O_4^2-= . oxalato )

JEE Main 2019 — Chemistry Inorganic Chemistry

2019mcqmedium

The coordination number of Th in K4[Th(C2O4)4(H2O)2]\mathrm{K}_{4}\left[\mathrm{Th}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{4}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]K4​[Th(C2​O4​)4​(H2​O)2​] is: (C2O42−=\left(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}=\right.(C2​O42−​= oxalato )))

Official previous-year question

Held on 11 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    14

  2. B

    6

  3. C

    8

  4. D

    10

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