Moles of CoCl3.6H2O=100×0.1×10−3=10−2mole
Moles of Cl− ions precipitated=6×10231.2×1022=2×10−2mole
So, one mole of complex will release two moles of chloride ions so, formula of complex is
[Co(H2O)5Cl]Cl2.H2O
On treatment of 100mL of 0.1M solution of CoCl3.6H2O with excess AgNO3;1.2×1022 ions are precipitated. The complex is:
Held on 2 Apr 2017 · Verified 6 Jul 2026.
[Co(H2O)3Cl3].3H2O
[Co(H2O)6Cl3]
[Co(H2O)5Cl]Cl2.H2O
[Co(H2O)4Cl2]Cl.2H2O
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