JEE Main 2016 — Chemistry Inorganic Chemistry

2016mcqmedium

Identify the correct trend given below:

(Atomic No. = Ti : 22, Cr : 24 and Mo : 42)

Official previous-year question

Held on 9 Apr 2016 · Verified 6 Jul 2026.

Options

A
$\Delta of {[Cr{({H}_{2}O)}_{6}]}^{2+}>{[Mo{({H}_{2}O)}_{6}]}^{2+}$ and $\Delta of {[Ti{({H}_{2}O)}_{6}]}^{3+}>{[Ti{({H}_{2}O)}_{6}]}^{2+}$
B
$\Delta of {[Cr{({H}_{2}O)}_{6}]}^{2+}>{[Mo{({H}_{2}O)}_{6}]}^{2+}$ and $\Delta of {[Ti{({H}_{2}O)}_{6}]}^{3+}<{[Ti{({H}_{2}O)}_{6}]}^{2+}$
C
$\Delta of {[Cr{({H}_{2}O)}_{6}]}^{2+}<{[Mo{({H}_{2}O)}_{6}]}^{2+}$ and $\Delta of {[Ti{({H}_{2}O)}_{6}]}^{3+}>{[Ti{({H}_{2}O)}_{6}]}^{2+}$
D
$\Delta of {[Cr{({H}_{2}O)}_{6}]}^{2+}<{[Mo{({H}_{2}O)}_{6}]}^{2+}$ and $\Delta of {[Ti{({H}_{2}O)}_{6}]}^{3+}<{[Ti{({H}_{2}O)}_{6}]}^{2+}$

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Solution

As the oxidation state of metal increases the CFSE value increases hence $\Delta \mathrm{of}{[\mathrm{Ti}{({H}_{2}O)}_{6}]}^{3+}>{[\mathrm{Ti}{({H}_{2}O)}_{6}]}^{2+}$

$\text{Δ}$ increase from 3d to 4d Series. So, $_{ }$ $\text{Δ} \propto$ CFSE (Crystal field stabilisation energy)

${\Delta \mathrm{of}[\mathrm{Cr}{({H}_{2}O)}_{6}]}^{2+}<\Delta of{[\mathrm{Mo}{({H}_{2}O)}_{6}]}^{2+}$

Because here $\text{Δ}$ depends on Z $_{eff}$ & Z $_{eff}$ of 4d series is more than 3d series

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Options

$\Delta of {[Cr{({H}_{2}O)}_{6}]}^{2+}>{[Mo{({H}_{2}O)}_{6}]}^{2+}$ and $\Delta of {[Ti{({H}_{2}O)}_{6}]}^{3+}>{[Ti{({H}_{2}O)}_{6}]}^{2+}$

$\Delta of {[Cr{({H}_{2}O)}_{6}]}^{2+}>{[Mo{({H}_{2}O)}_{6}]}^{2+}$ and $\Delta of {[Ti{({H}_{2}O)}_{6}]}^{3+}<{[Ti{({H}_{2}O)}_{6}]}^{2+}$

$\Delta of {[Cr{({H}_{2}O)}_{6}]}^{2+}<{[Mo{({H}_{2}O)}_{6}]}^{2+}$ and $\Delta of {[Ti{({H}_{2}O)}_{6}]}^{3+}>{[Ti{({H}_{2}O)}_{6}]}^{2+}$

$\Delta of {[Cr{({H}_{2}O)}_{6}]}^{2+}<{[Mo{({H}_{2}O)}_{6}]}^{2+}$ and $\Delta of {[Ti{({H}_{2}O)}_{6}]}^{3+}<{[Ti{({H}_{2}O)}_{6}]}^{2+}$

Solution

As the oxidation state of metal increases the CFSE value increases hence $\Delta \mathrm{of}{[\mathrm{Ti}{({H}_{2}O)}_{6}]}^{3+}>{[\mathrm{Ti}{({H}_{2}O)}_{6}]}^{2+}$

$\text{Δ}$ increase from 3d to 4d Series. So, $_{ }$ $\text{Δ} \propto$ CFSE (Crystal field stabilisation energy)

${\Delta \mathrm{of}[\mathrm{Cr}{({H}_{2}O)}_{6}]}^{2+}<\Delta of{[\mathrm{Mo}{({H}_{2}O)}_{6}]}^{2+}$

Because here $\text{Δ}$ depends on Z $_{eff}$ & Z $_{eff}$ of 4d series is more than 3d series

JEE Main 2016 — Chemistry Inorganic Chemistry

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JEE Main 2016 — Chemistry Inorganic Chemistry

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