Electron density between nuclei increased during formation of BMO in H2 .
BMO is ψA+ψB (Linear combination of Atomtextc orbitals) provides constructive interference.
While by distructive interference anti BMO ψA−ψB formed.
JEE Main 2015 — Chemistry Inorganic Chemistry
After understanding the assertion and reason, choose the correct option.
Assertion: In the bonding molecular orbital (MO) of H2, electron density is increased between the nuclei.
Reason: The bonding MO is ψA+ψB , which shows destructive interference of the combining electron waves.
Held on 10 Apr 2015 · Verified 6 Jul 2026.
Assertion and Reason are correct, but Reason is not the correct explanation for the Assertion.
Assertion and Reason are correct and Reason is the correct explanation for the Assertion.
Assertion is incorrect, Reason is correct.
Assertion is correct, Reason is incorrect.
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
It is noticed that $\mathrm{Pb}^{2+}$ is more stable than $\mathrm{Pb}^{4+}$ but $\mathrm{Sn}^{2+}$ is less stable than $\mathrm{Sn}^{4+}$. Observe the following reactions. $\mathrm{PbO}_{2}+\mathrm{Pb} \rightarrow 2 \mathrm{PbO} ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ}(1)$ $\mathrm{SnO}_{2}+\mathrm{Sn} \rightarrow 2 \mathrm{SnO} ; \Delta_{\mathrm{r}} \mathrm{G}^{\circ}(2)$ Identify the correct set from the following
In a period, the first ionisation enthalpy of the element at extreme left and the negative electron gain enthalpy of the extreme right element, except noble gases, are respectively.
First and second ionization enthalpies of lithium are $520$ kJ mol$^{-1}$ and $7297$ kJ mol$^{-1}$ respectively. Energy required to convert $3.5$ mg lithium (g) into $\text{Li}^{2+}$(g) $[\text{Li(g)} \rightarrow \text{Li}^{2+}\text{(g)}]$ is _______ kJ mol$^{-1}$. (nearest integer) [Molar mass of Li $= 7$ g mol$^{-1}$]
Which of the following elements has the highest electronegativity?
On heating a mixture of common salt and $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ in equal amount along with concentrated $\mathrm{H}_{2} \mathrm{SO}_{4}$ in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas respectively are:
Work through every JEE Main Inorganic Chemistry PYQ, year by year.