The bond order of N2,O2, and O2−are respectively 3,2 and 1.5 Since higher bond order implies higher bond dissociation energy hence the correct order will be N2>O2>O2−
The correct order of bond dissociation energy among N2,O2,O2−is shown in which of the following arrangements?
Held on 11 Apr 2014 · Verified 6 Jul 2026.
N2>O2−>O2
O2−>O2>N2
N2>O2>O2−
O2>O2−>N2
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