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Bond distance in HF is 9.17 × 10^-11 ~m. Dipole moment of HF is 6.104 × 10^-30 Cm. The percentage ionic character in HF will be : (electron charge…

JEE Main 2013 — Chemistry Inorganic Chemistry

2013mcqhard

Bond distance in HF\mathrm{HF}HF is 9.17×10−11 m9.17 \times 10^{-11} \mathrm{~m}9.17×10−11 m. Dipole moment of HF\mathrm{HF}HF is 6.104×10−30Cm6.104 \times 10^{-30} \mathrm{Cm}6.104×10−30Cm. The percentage ionic character in HF\mathrm{HF}HF will be : (electron charge =1.60×10−19C=1.60 \times 10^{-19} \mathrm{C}=1.60×10−19C )

Official previous-year question

Held on 23 Apr 2013 · Verified 6 Jul 2026.

Options

  1. A

    61.0%61.0 \%61.0%

  2. B

    38.0%38.0 \%38.0%

  3. C

    35.5%35.5 \%35.5%

  4. D

    41.5%41.5 \%41.5%

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