Cr2O72−+OH−→2CrO42−+H+. The above equilibrium shifts to L.H.S. on addition of acid.
JEE Main 2003 — Chemistry Inorganic Chemistry
What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?
Held on 30 Apr 2003 · Verified 6 Jul 2026.
Cr2O72− and H2O are formed
CrO2−4 is reduced to +3 state of Cr
CrO42− is oxidized to +7 state of Cr
Cr3+ and Cr2O2−7 are formed
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