Electronic configuration of Cr is 
So due to half filled orbital I.P. is high of Cr.
The atomic numbers of vanadium (V), Chromium (Cr), manganese (Mn) and iron (Fe) are respectively 23 , 24,25 and 26 . Which one of these may be expected to have the highest second ionization enthalpy?
Held on 30 Apr 2003 · Verified 6 Jul 2026.
Cr
Mn
Fe
V
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First and second ionization enthalpies of lithium are $520$ kJ mol$^{-1}$ and $7297$ kJ mol$^{-1}$ respectively. Energy required to convert $3.5$ mg lithium (g) into $\text{Li}^{2+}$(g) $[\text{Li(g)} \rightarrow \text{Li}^{2+}\text{(g)}]$ is _______ kJ mol$^{-1}$. (nearest integer) [Molar mass of Li $= 7$ g mol$^{-1}$]
Regarding the hydrides of group 15 elements $\mathrm{EH}_{3}(\mathrm{E}=\mathrm{N}, \mathrm{P}, \mathrm{As}, \mathrm{Sb})$, select the correct statement from the following: A. The stability of hydrides decreases down the group. B. The basicity of hydrides decreases down the group. C. The reducing character increases down the group. D. The boiling point increases down the group. Choose the correct answer from the options given below:
Which of the following elements has the highest electronegativity?
Which of the following elements has the highest electronegativity?
In a period, the first ionisation enthalpy of the element at extreme left and the negative electron gain enthalpy of the extreme right element, except noble gases, are respectively.
Work through every JEE Main Inorganic Chemistry PYQ, year by year.