Angular momentum of electron moving in nth orbit of hydrogen atom 
Hence, n=3 Now, energy of electron in 3rd orbit E=n2−13.6×z2=32−13.6×12=−1.51eV≈−1.5eV
The angular momentum of an electron moving in an orbit of hydrogen atom is 1.5(πh). The energy in the same orbit is nearly
Held on 30 Apr 2023 · Verified 9 Jul 2026.
−1.3eV
−1.4eV
−1.5eV
−1.6eV
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De-Broglie wavelength of an electron orbiting in the $n=2$ state of hydrogen atom is close to (Given Bohr radius $=0.052 \mathrm{~nm}$ )
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