Given,
T21=100hours
t=150hours
As we know that the number of nuclide remain after n half life is given by,
N=2nN0
∵100 hours =1 half life
150 hours=1001×150
=23 half life
So, Fraction remain after 23 half life
N0N=(21)3/2=221
The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be :
Held on 30 Apr 2021 · Verified 9 Jul 2026.
21
221
32
322
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