Given binding energy per nucleon of X,Y&Z are, 7.6M\mathrm{eV},8.5M\mathrm{eV}&8.5M\mathrm{eV} respectively.
⇒B.E. =(120×8.5)+(120×8.5)−240×7.6
⇒B.E.=2040−1824=216MeV
NEET UG 2021 — Physics Modern Physics
A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6MeV while that of fragments is 8.5MeV. The total gain in the binding energy in the process is :
Held on 30 Apr 2021 · Verified 9 Jul 2026.
0.9MeV
9.4MeV
216MeV
804MeV
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