The energy of light of wavelength λ is given by E=hv=λhc⇒λ=Ehc Here, h= Planck's constant =6.63×10−34 J−s c= speed of light =3×108 m/s E= energy gap =1.9eV=1.9×1.6×10−19 J Substituting the given values in Eq. (i), we get ⇒λ=1.9×1.6×10−196.63×10−34×3×108=6.54×10−7 m≈654 nm Thus, the wavelength of light emitted from LED will be 654 nm.