Momentum, P=λh⇒E=2mP2⇒2mλ2h2=λ0hc
⇒λ0=h2hc2mλ2
=h2mcλ2.
Electrons of mass, m with de-Broglie wavelength, λ fall on the target in an X-ray tube. The cutoff wavelength, (λ0) of the emitted X-ray is
Held on 30 Apr 2016 · Verified 9 Jul 2026.
λ0=h2mcλ2
λ0=mc2h
λ0=h22m2c2λ3
λ0=λ
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