Wavelength for Lyman series λL=R(1−41)1=3R4 and wavelength for Balmer series λB=R(41−91)1=R(365)1=5R36∴λBλL=3R4×365R=275⇒λL:λB=5:27
Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is
NEET UG 2013 — Physics Modern Physics
2013mcqmedium
Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is
Official previous-year question
Held on 30 Apr 2013 · Verified 9 Jul 2026.
Options
- A
275
- B
233
- C
297
- D
319
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