Time period of an electron in Bohr orbit is ⇒T⇒T2T1T=me44ε02h3n3∝n3=n23n13 As T1=8T2 then ⇒⇒⇒⇒(T28T2)(n2n1)3n2n1n1=n23n13=(22)3=22=2n2
NEET UG 2013 — Physics Modern Physics
An electron in hydrogen atom makes a transition n1→n2 where n1 are principle quantum numbers of the two states. Assuming Bohr's model to be valid, the time period of the electron in the initial state is eight times that in the final state. The possible values of n1 and n2 are:
Held on 30 Apr 2013 · Verified 9 Jul 2026.
n1=6 and n2=2
n1=8 and n2=1
n1=4 and n2=2
n1=4 and n2=2
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
A particle of mass $m$ is moving around the origin with a constant force $F$ pulling it towards the origin. If Bohr model is used to describe its motion, the radius $r$ of the $n^{\text {th }}$ orbit and the particle's speed $v$ in the orbit depend on $n$ as
A full wave rectifier circuit with diodes $\left(D_1\right)$ and $\left(D_2\right)$ is shown in the figure. If input supply voltage $V_{\text {in }}=220 \sin (100 \pi t)$ volt, then at $t=15 \mathrm{msec}$ 
The maximum kinetic energy of photoelectrons from a surface with work function φ = 2 eV when light of λ = 4000 Å falls on it is (hc = 12400 eV·Å):
A photon and an electron (mass $m$ ) have the same energy $E$. The ratio ( $\lambda_{\text {photon }} / \lambda_{\text {electron }}$ ) of their de Broglie wavelengths is: (c is the speed of light)
The output $(\mathrm{Y})$ of the given logic implementation is similar to the output of an/a _____ gate. 
Work through every NEET UG Modern Physics PYQ, year by year.