Here, for wavelength λ1 n1=4 and n2=3 and for λ2,n1=3 and n2=2 We have λhc=−13.6[n221−n121] So, for λ1 ⇒λ1hcλ1hc=−13.6[(4)21−(3)21]=13.6[1447] Similarly, for λ2 ⇒λ2hcλ2hc=−13.6[(3)21−(2)21]=13.6[365] Hence, from Eqs. (i) and (ii), we get λ2λ1=720
Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state. The…
NEET UG 2012 — Physics Modern Physics
2012mcqmedium
Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state. The ratio of the wavelengths λ1:λ2 emitted in the two cases is
Official previous-year question
Held on 30 Apr 2012 · Verified 9 Jul 2026.
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27/20
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