Let assume power P=1000 W Energy per hour =1000×3600 J Energy per fission =200MeV =200×1.6×10−13 J ∴ Number of fission per hour n=200×1.6×10−131000×3600 Number of mole per hour =Nn∴ Mass per hour =Nn×235 =200×1.6×10−13×6.02×10231000×3600×235=43.9×10−6 g This 43.9×10−6 g is nearest value of 40 micro gram so option (b) is correct.
The power obtained in a reactor using U^235 disintegration is 1000 ~kW. The mass decay of U^235 per hour is
NEET UG 2011 — Physics Modern Physics
2011mcqeasy
The power obtained in a reactor using U235 disintegration is 1000 kW. The mass decay of U235 per hour is
Official previous-year question
Held on 30 Apr 2011 · Verified 9 Jul 2026.
Options
- A
20μg
- B
40μg
- C
1μg
- D
10μg
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