Kinetic energy KE=ϕ−ϕ0 Here, KE1=1−0.5=0.5eV KE2=2.5−0.5=2eV∴KE2KE1=20.5=41 or y22y12=41 or y2y1=41=21
Light of two different frequencies whose photons have energies 1eV and 2.5eV respectively illuminate a metallic surface whose work function is 0.5eV successively. Ratio of maximum speeds of emitted electrons will be
Held on 30 Apr 2011 · Verified 9 Jul 2026.
1:2
1:1
1:5
1:4
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