For n=1,E1=−(1)213.6=−13.6eV and for n=3,E3=−(3)213.6=−1.51eV So, required energy E=E3−E1=−(1.51)−(−13.6)=12.09eV∵E=W+eV∴eV=E−WeV=(12.09−51)e=7 volt
The electron in the hydrogen atom jumps from excited state (n=3) to its ground state (n=1) and the photons thus emitted irradiate a photosensitive material. If the work function of the material is 5.1eV, the stopping potential is estimated to be (the energy of the electron in nth state En=−n213.6eV )
Held on 30 Apr 2010 · Verified 9 Jul 2026.
5.1 V
12.1 V
17.2 V
7 V
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