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NEET UG 2010 — Modern Physics

Physics Modern Physics questions from NEET UG 2010.

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14 Modern Physics Questions from 2010

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function $5.01 \mathrm{eV}$, when ultraviolet light of $200 \mathrm{~nm}$ falls on it, must be

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The mass of a ${ }_3 \mathrm{Li}^7$ nucleus is $0.042 \mathrm{u}$ less than the sum of the masses of all its nucleons. The binding energy per nucleon of ${ }_3 \mathrm{Li}^7$ nucleus is nearly

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The energy of a hydrogen atom in the ground state is $-13.6 \mathrm{eV}$. The energy of a $\mathrm{He}^{+}$ion in the first excited state will be

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A source $\mathrm{S}_1$ is producing, $10^{15}$ photons/s of wavelength $5000 Å$. Another source $S_2$ is producing $1.02 \times 10^{15}$ photons per second of wavelength $5100 Å$. Then, (power of $\left.S_2\right) /\left(\right.$ power of $S_1$ ) is equal to

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To get an output $Y=1$ from the circuit shown below, the input must be ![NEET 2010 Physics, Semiconductors — question figure 1](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/616059730283de43c87e3e22/Physics/images/Semiconductors/66bcbe94ae81d148616b1a6e/question_1__q_66bcbe94ae81d148616b1a6e__cdn-question-pool.getmarks.app__zakwtMUW-tuZ8rJxjVf_ApmGu9-UTisw4ACkZnlUHUc.original.fullsiz__0e340e2acf_final_ppt_sync.png) ![NEET 2010 Physics, Semiconductors — question figure 2](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/616059730283de43c87e3e22/Physics/images/Semiconductors/66bcbe94ae81d148616b1a6e/question_2__q_66bcbe94ae81d148616b1a6e__cdn-question-pool.getmarks.app__vVGLf6X7L_PQmHGC47EEGtgfyY4Hiw1sibGmg_wisQY.original.fullsiz__a5fda32891_final_ppt_sync.png)

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When monochromatic radiation of intensity $I$ falls on a metal surface, the number of photoelectron and their maximum kinetic energy are $N$ and $T$ respectively. If the intensity of radiation is 2I, the number of emitted electrons and their maximum kinetic energy are respectively

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The following figure shows a logic gate circuit with two inputs $A$ and $B$ and the output $Y$. The voltage waveforms of $A, B$ and $Y$ are as given ![NEET 2010 Physics, Semiconductors — question figure 1](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/616059730283de43c87e3e22/Physics/images/Semiconductors/66bcbe7eae81d148616b19c0/question_1__q_66bcbe7eae81d148616b19c0__cdn-question-pool.getmarks.app__ZzcZZf3aFJwufr3bJyfoXlNekIG6r9gxbgdNJjvAlzY.original.fullsiz__c9e5140493_final_ppt_sync.png) ![NEET 2010 Physics, Semiconductors — question figure 2](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/616059730283de43c87e3e22/Physics/images/Semiconductors/66bcbe7eae81d148616b19c0/question_2__q_66bcbe7eae81d148616b19c0__cdn-question-pool.getmarks.app__iaH12gIrayBuchc9yfJG_NCNjuUieQ-dcaj10lbML9Q.original.fullsiz__eac0936ad9_final_ppt_sync.png) The logic gate is

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Which one of the following statement is false?

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The device that can act as a complete electronic circuit is

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The electron in the hydrogen atom jumps from excited state $(n=3)$ to its ground state $(n=1)$ and the photons thus emitted irradiate a photosensitive material. If the work function of the material is $5.1 \mathrm{eV}$, the stopping potential is estimated to be (the energy of the electron in $n$th state $\mathrm{E}_{\mathrm{n}}=-\frac{13.6}{\mathrm{n}^2} \mathrm{eV}$ )

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The activity of a radioactive sample is measured as $\mathrm{N}_0$ counts per minute at $\mathrm{t}=0$ and $\mathrm{N}_0 / \mathrm{e}$ counts per minute at $\mathrm{t}=5 \mathrm{~min}$. The time (in minute) at which the activity reduces to half its value is

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The binding energy per nucleon in deuterium and helium nuclei are $1.1 \mathrm{MeV}$ and $7.0 \mathrm{MeV}$, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is

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The decay constant of a radio isotope is $\lambda$. If $A_1$ and $\mathrm{A}_2$ are its activities at times $\mathrm{t}_1$ and $\mathrm{t}_2$ respectively, the number of nuclei which have decayed during the time $\left(\mathrm{t}_1-\mathrm{t}_2\right)$

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A beam of cathode rays is subjected to crossed Electric ( $E$ ) and Magnetic fields $(B)$. The fields are adjusted such that the beam is not deflected. The specific charge of the cathode rays is given by (where $V$ is the potential difference between cathod and anode)

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