Number of photons emitted per second n=(λhc)P∴P=λnhc⇒P1P2=n1λ2n2λ1=1015×51001.02×1015×5000=1
A source S_1 is producing, 10^15 photons/s of wavelength 5000 Å. Another source S_2 is producing 1.02 × 10^15 photons per second of wavelength 5100…
NEET UG 2010 — Physics Modern Physics
2010mcqmedium
A source S1 is producing, 1015 photons/s of wavelength 5000A˚. Another source S2 is producing 1.02×1015 photons per second of wavelength 5100A˚. Then, (power of S2)/( power of S1 ) is equal to
Official previous-year question
Held on 30 Apr 2010 · Verified 9 Jul 2026.
Options
- A
1.00
- B
1.02
- C
1.04
- D
0.98
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