Nuclear radii R=(R0)A1/3 where, A is the mass number. RAlRTe=(AAlATe)1/3=(27125)1/3=(35) or, RTe=35×RAl=35×3.6=6fm. (Given RAl=3.6fm)
If the nucleus 1327Al has a nuclear radius of about 3.6fm, then 32125Te would have its radius approximately as:
Held on 30 Apr 2007 · Verified 9 Jul 2026.
9.6fm
12.0fm
4.8fm
6.0fm.
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