In the case of formation of a nucleus the evolution of energy equal to the binding energy of the nucleus takes place due to disappearance of a fraction of the total mass. If the quantity of mass disappearing is ΔM. then the binding energy is BE=ΔMc2 From the above discussion, it is clear that the mass of the nucleus must be less than the sum of the masses of the constituent neutrons and protons. We can then write ΔM=ZMp+NMp−M(A,Z) Where M(A,Z) is the mass of the atom of mass number A and atomic number Z. Hence, the binding energy of the nucleus is BE=[ZMp+NMn−M(A,Z)]c2BE=[ZMp+(A−Z)Mn−M(A,Z)]c2 Where N=A−Z= Number of neutrons.
A nucleus ^A_Z X has mass represented by M(A, Z). If M_p and M_n denote the mass of proton and neutron respectively and B.E. the binding energy in…
NEET UG 2007 — Physics Modern Physics
2007mcqeasy
A nucleus ZAX has mass represented by M(A,Z). If Mp and Mn denote the mass of proton and neutron respectively and B.E. the binding energy in MeV, then
Official previous-year question
Held on 30 Apr 2007 · Verified 9 Jul 2026.
Options
- A
B. E. =[ZMp+(A−Z)Mn−M(A,Z)]c2
- B
B. E. =[ZMp+AMn−M(A,Z)]c2
- C
B. E. =M(A,Z)−ZMp−(A−Z)Mn
- D
B. E. =[M(A,Z)−ZMp−(A−Z)Mn]c2.
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