Total force along inclined plane, ffffacceleration, a=−F1+6gsin30∘+F2=−60+6gsin30∘+18=−60+6×10×21+18=12 N (downwards) =mf=612=2 m/s2 
As per question, the normal force between 2 kg and 1 kg is, N−18−10sin30∘ N−18−10×21 N N=ma=1×2=2+23=25 N
NEET UG 2022 — Physics Mechanics
2022mcqmedium
In the diagram shown, the normal reaction force between 2 kg and 1 kg is (Given g=10 ms−2) (Consider the surface, to be smooth): 
Official previous-year question
Held on 30 Apr 2022 · Verified 9 Jul 2026.
Options
- A
25 N
- B
39 N
- C
6 N
- D
10 N
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